i have custom members system have made: yii2 members system . can refer full details, or install can work question. i have frontend , backend yii2 provides, few modifications separate sessions/cookies backend works admin model , pulls admin table. similar old traditional member systems. mainsite clone of frontend , it's role main website. when go www.site.com or site.com . here 3 apps , example domains: mainsite = www.site.com or site.com frontend = users.site.com backend = admin.site.com when user logs in ( users.site.com/site/login ) , go homepage ( mainsite @ www.site.com ) want know logged in , show username. how frontend operates default advanced app. from have far, login , head mainsite , reads an internal server error occurred. . doesn't yii error, server error? when in yii logs under runtime, mentions access control: 2017-04-14 13:38:25 [127.0.0.1][1][-][error][yii\web\httpexception:403] exception 'yii\web\forbiddenhttpexception'...
i need check whether password , confirm password fields have same value using reactive form angular2. did see lot of answers on same here, angular 2 form validating repeat password , comparing fields in validator angular2 , none seemed work me.can please help."this" undefined in validate function :( . sharing code, this.addedituserform = this.builder.group({ firstname: ['', validators.required], lastname: ['', validators.required], title: ['', validators.required], email: ['', validators.required], password: ['', validators.required], confirmpass: ['', [validators.required, this.validatepasswordconfirmation]] }); validatepasswordconfirmation(group: formgroup): any{ let valid = true; // if (this.addedituserform.controls.password != this.addedituserform.controls.confirmpass) { // valid = false; // this.add...
i have page named 'posts_list.php' containing list of blog posts retrieved form json api have id, title, image etc . have link on page goes page called 'post.php' below: <a href="post.php?id=<?php echo $post->id ?> "> using method can retrieve 'id' of post clicked user using: <?php $postid = $_get['id']; ?> what want display json post on post.php corresponds id retrieved link on posts_list.php i know sql use clause, being new json im not sure if possible. need achieve php , json it has info /v1/blogs/@blog/@id @blog - blog identifier @id - blog post id
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