Reading data from a python socket received from multiple clients -

i writing python program (master.py) read data received 2 separate clients. code example:

master.py:

data_agg = '' host = '172.31.31.207' port = 50008 s = socket.socket(socket.af_inet, socket.sock_stream) s.bind((host, port)) s.listen(2) conn, addr = s.accept() print 'connected by', addr while 1:     data = conn.recv(65535)     data_agg += data     if not data: break  data_arr = json.loads(data_agg.decode('utf-8')) data_arr = sorted(data_arr) print "sorted attay: \n" print data_arr 

two clients have following code:

host = '172.31.31.207' port = 50008 s0 = socket.socket(socket.af_inet, socket.sock_stream) s0.connect((host, port)) s0.send(sorted_data_string) s0.close() 

however receive data single client. proper way read data socket arriving multiple receivers?

i modified code bit , can handle 2 or more clients.
, suggest calling accept on main thread , , recv on seperate thread task

data_agg = [] host = '172.31.31.207' port = 50008 s = socket.socket(socket.af_inet, socket.sock_stream) s.bind((host, port)) s.listen(2) in range(2) : ## can change number accept more clients     conn, addr = s.accept()     print 'connected by', addr     data_received = ''     while 1:         data = conn.recv(65535)         if not data or len(data) == 0 :              break         data_received += data     data_agg += [ data_received ]       conn.close() s.close()  d in data_agg :      data_arr = json.loads(d.decode('utf-8'))     data_arr = sorted(data_arr)     print "sorted attay: \n"     print data_arr 

you improve above code using thread , can handle multiple clients simultaneously .
can defining handle_client function , , run on new thread .

while true :      conn, addr = s.accept()     print 'connected by', addr     start_new_thread(handle_client, (conn,))