Can someone help me with the Sublist Predicate (Prolog)? -

i want implement predicate sublist1(i1,i2,l,sub) takes list l , returns sub includes elements of l index i1 index i2. code gives me false time . idea what's wrong?

sublist1(0,0,[h|t],[h|sub]).   sublist1(i1,i2,[h|t],sub):-    i1 =0, i2>=i1,    i2-1,    sublist1(i1,i,t,[h|sub]).  sublist1(i1,i2,[h|t],_):-   i1>0, i2>i1,   ii1 i1-1,   ii2 i2-1,   sublist1(ii1,ii2,t,_). 

algorithmically, should work :

% sublist 0 0 should return [h] list sublist1(0,0,[h|t],[h]).  % sublist 0 n should return first element followed sublist 0 n-1 of tail sublist1(i1,i2,[h|t],[h|sub]):-     i1 0, i2 > 0,     ii2 i2 - 1,     sublist1(i1,ii2,t,sub).  % sublist of [h|t] i1 i2 should return sublist i1-1 i2-1 of t sublist1(i1,i2,[h|t],sub):-   i1>0, i2>i1,   ii1 i1-1,   ii2 i2-1,   sublist1(ii1,ii2,t,sub). 

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edit

try online (run execute , write sublist1(2,5,[0,1,2,3,4,5,6,7,8],s). example). use alt+91 [ , alt+93 ]