debugging - C++ Heap/Stack. Why only one new-operator? -

i'm starting learn topic of dynamic memory allocation.

i have following code:

#include <iostream> #include "a.h" #include "b.h"  using namespace std;  int main() {     /* both objects on stack */     classastack;    b classbstack;     /* both objects on heap*/    //  *classaheap = new a();    //  b *classbheap = new b();     /* objects on heap b ???*/    *classaheap = new a();     return 0; } 

#ifndef a_h_ #define a_h_  #include <iostream> #include "b.h"  class { public:    a();    virtual ~a();  public:    b b; };  #endif /* a_h_ */ 

#include "a.h"  a::a() {    std::cout <<"constructor called" << std::endl; }  a::~a() { } 

#ifndef b_h_   #define b_h_  #include <iostream>  class b { public:   b();   virtual ~b(); };  #endif /* b_h_ */ 

#include "b.h"  b::b() {   std::cout <<"constructor b called" << std::endl; }  b::~b() { } 

the output of debugger is:

 temporary breakpoint 6, main () @ ../src/heapstacktest02.cpp:18 18    classastack;  breakpoint 4, b::b (this=0x23aa58) @ ../src/b.cpp:12 12    std::cout <<"constructor b called" << std::endl;  breakpoint 5, a::a (this=0x23aa50) @ ../src/a.cpp:13 13    std::cout <<"constructor called" << std::endl;  breakpoint 4, b::b (this=0x23aa40) @ ../src/b.cpp:12 12    std::cout <<"constructor b called" << std::endl;  breakpoint 4, b::b (this=0x60004b048) @ ../src/b.cpp:12 12    std::cout <<"constructor b called" << std::endl;  breakpoint 5, a::a (this=0x60004b040) @ ../src/a.cpp:13 13    std::cout <<"constructor called" << std::endl;  breakpoint 1, main () @ ../src/heapstacktest02.cpp:30 30    return 0; 

to question:

where member-variable b of class a?

if @ address in section 0x23a, seems stack, , section 0x6000 seems heap.

i'm working on windows 64-bit system.

why member-variable b on heap, without new operator being called?