c# - Linq order by random without GUID -

need order random using linq , can't use guid.newguid(), need this: .orderby(x => "somestring").

a mobile app suppose generate random string , call webapi , because maintained paging mobile app sends same random string different page number every time sends random string ordering should same different skip ... .

how possible? if not string maybe number or fixed every linq query.

edit:

this webapi

[route("getchannels/{id}/{word}/{page}/{randomstring}")] public ienumerable<channels> getchannels(int id, string word, int page, string randomstring)     {     ...      if (canpage)        {                             var channels = db.channels.where(x => (id == 0) || (x.categoryid == id))             .where(q => word == "0" ||             (q.title.contains(word) || q.desc.contains(word)))             .orderby(x => randomstring).skip(skip).take(pagesize).tolist();         }  ... 

if want return results in random order, order same if sending same string client, can use random class pseudo-random order. random generator can accept seed - value, used calculate starting value of pseudo-random sequence. passing string can use it's hash code integer value seed:

        var seed = randomstring.gethashcode();         var random = new random(seed);          var channels = db.channels            .where(x => (id == 0) || (x.categoryid == id))            .where(q => word == "0" || (q.title.contains(word) || q.desc.contains(word)))            .asenumerable() // randomizing should happen on client side            .orderby(x => random.next())            .skip(skip)            .take(pagesize)            .tolist();