python - Sorting an imported list not working -

i trying sort imported list display have tried sorts of things , didnt work.

here exemple of list:

pommes : 54 bananes : 18 oranges : 30   ananas :12 clémentines    :77 cerises de terre:    43 

the output should ordered alphabeticaly

this getting

['\n', '\n', '\n', '\n', '\n', '\n', '\n', '\n', '\n', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', '0', '1', '1', '2',  '3', '3', '4', '4', '5', '7', '7', '8', ':', ':', ':', ':', ':', ':', 'a', 'a', 'a', 'a', 'a', 'a', 'b', 'c', 'c', 'd', 'e', 'e', 'e', 'e', 'e', 'e', 'e', 'e' , 'e', 'e', 'g', 'i', 'i', 'l', 'm', 'm', 'm', 'n', 'n', 'n', 'n', 'n', 'n', 'n', 'o', 'o', 'p', 'r', 'r', 'r', 'r', 's', 's', 's', 's', 's', 's', 's', 't', 't ', 'é'] 

here's code

import sys  def liste(entree):     try:         ouvrir = open("data2.txt")     except ioerror:         message1 = "le fichier data2 n'existe pas."         return message1     lecture = ouvrir.read()     if len(entree) < 1:         message2 = "il faut préciser le nom du fichier à traiter"         return message2     elif len(entree) > 1:         message3 = "un seul argument est attendu, soit le nom du fichier à traiter."         return message3     else:         return lecture  def main():     while true:         entree = sys.argv[1:]         choix = str(entree)         texte = "data2.txt"         if texte in choix:             message4 = liste(entree)             message4 = sorted(message4)             print(message4)             break         else:             print("il faut préciser le nom du fichier à traiter")             exit()  if __name__ == "__main__":     main() 

try readlines, (see answer: how read file line-by-line list?, see: reading text file , splitting single words in python).

oh, , 'with open()' idiomatic (moreso try),

with open("data2.txt") ouvrir:     lines = ouvrir.readlines() print sorted(lines) 

assuming each line contains single word, done.

suppose want treat each line words (one or more words per line), sort words on each line, , sort lines,

#open file "data2.txt" , readlines list #split each line words , sort list of sorted lines #words = list ( list ( word ) ) open("data2.txt") ouvrir:     lines = ouvrir.readlines()     line_words = [ x x in [ line.split(":") line in lines ] ]     #line_names = [ x[0] x in [ line.split(":") line in lines ] ] print sorted(line_words) 

suppose each line has 1 or more words, , want sorted list of words? following flattens nested list of words single list of words,

#open file "data2.txt" , readlines list #split each line words, flatten single list of words #words = list ( word ) open("data2.txt") ouvrir:     lecture = ouvrir.readlines()     words = [ word line in lecture word in line.split() ] print sorted(words) 

suppose lines have key:value pairs, e.g. "apple: 23"?, want different

your program combines examining entree (slice sys.argv[1:]) opening , reading file. should separate 2 functions. here 1 way revise code,

import sys  def liste(texte,entree):     if len(entree) < 1:         return "il faut préciser le nom du fichier à traiter"     elif len(entree) > 1:         return "un seul argument est attendu, soit le nom du fichier à traiter."     open(texte) ouvrir:         lecture = ouvrir.readlines()         words = [ x.split(":")[0].strip() x in [ line.strip() line in lecture ] ]         words = [ x x in words if len(x) > 1 ] #filter, remove short words (blanks)         return lecture     return "le fichier {} n'existe pas.".format(texte)  def main():     while true:         entree = sys.argv[1:]         choix = str(entree)         texte = "data2.txt"         if texte in choix:             message4 = sorted(liste(texte,entree))             print(message4)             el in message4: print(el)             break         else:             print("il faut préciser le nom du fichier à traiter")             break  if __name__ == "__main__":     main()     exit()