linux - Fastest way to delete files from a directory tree whose names contain a certain string -

i have directory containing subdirectories delete files names contain out. fastest method of doing this?

i have tried several things.

a simple:

rm */*out* 

perl:

perl -e 'for ( <*/*out*> ) { ( (stat)[9] < (unlink) ) }' 

each of seem take serious amount of time. 1,000 subdirectories, each of contain around 50 files matching *out*, takes:

perl:        ~25 mins rm */*out* : ~18 mins 

i tried rsync, moving files folder first , syncing delete, took ages.

does have faster way of getting rid of these files, seems inordinately slow me?

i find test3 fastest (11-25 sec). why not test yourself?

your filesystem can have big impact on performance.

the test uses gnu parallel.

# make test set: 150000 files, 50000 named *.seq testset() {   doit() { mkdir -p $1 ; cd $1 && parallel --results ./{} seq ::: {1..50}; }   export -f doit   seq 1000 | parallel --bar doit >/dev/null    # drop caches before starting test   echo 3 | sudo tee /proc/sys/vm/drop_caches >/dev/null } export -f testset  # define tests test1() {   find . -name '*seq' | perl -ne 'chop;unlink' } export -f test1 test2() {   find . -name '*seq' -delete } export -f test2 test3() {   find . -name '*seq' | parallel --pipe -n1000 -q perl -ne 'chop;unlink' } export -f test3 test4() {   find . -name '*seq' -print0 | xargs -0 -p2 rm } export -f test4 test5() {   find . -name '*seq' -print0 | xargs -0 rm } export -f test5 test6() {   find . -name '*seq' | perl -e 'chomp(@a=<>);unlink @a' } export -f test6 test7() {   # sort inode   ls -u -i */*seq* | sort -k1,1 -n| cut -d' ' -f2- | perl -e 'chomp(@a=<>);unlink @a' } export -f test7  # run testset/test? alternating eval parallel --joblog jl -uj1 ::: testset' 'test{1..7}  # sort runtime sort -nk4 jl