ascii - Printing characters to LCD - Verilog HDL -

i have question regarding printing character lcd screen.

i using altera de1-soc 5csema5f31c6n , lt24 terasic lcd.

i have question regarding printing letters in row on lcd.

i relying on x , y counter raster across screen, starting @ (0,0) upper left corner of screen. incrementing x way end of row, , once reached end, reset x 0, increment y , continue counting x again until end of screen

lcd pixels

i creating arrays print character values (8x8 px)

the long array concatenates 'each row of pixels' characters, , whilst counter rastered across screen pixels each character print lcd.

eg. row0 - print first row of pixels characters. row1 - print second row of pixels characters.

however, when try print 2 characters, order of characters being printed reversed [from origin (0,0)]

e.g. if want print 'i' 'm'. 'm' , 'i' in order.

when try print 3 characters, no characters show @ all!

i struggling understand why case, counter values used test current bit of character , draw pixel

any appreciated.

i have basic verilog understanding, comfortable c programming

thank you,

code snippets below.

////////////////////////////// code //////////////////////////////////////////// reg [0] totalchardata [23:0];   //   pixel row0 reg [1] totalchardata [23:0];   //   pixel row1 reg [2] totalchardata [23:0];   //  pixel row2 reg [3] totalchardata [23:0];   //   pixel row3 reg [4] totalchardata [23:0];   //    reg [5] totalchardata [23:0];   //    reg [6] totalchardata [23:0];   //    reg [7] totalchardata [23:0];   // pixel row 7      // character  ‘i'     totalchardata[7][7:0] = 8'b11111111;     totalchardata[6][7:0] = 8'b11111111;     totalchardata[5][7:0] = 8'b00111100;     totalchardata[4][7:0] = 8'b00111100;     totalchardata[3][7:0] = 8'b00111100;     totalchardata[2][7:0] = 8'b00111100;     totalchardata[1][7:0] = 8'b11111111;     totalchardata[0][7:0] = 8'b11111111;      // character ‘m'     totalchardata[7][15:8] = 8'b11100111;     totalchardata[6][15:8] = 8'b11101111;     totalchardata[5][15:8] = 8'b11111111;     totalchardata[4][15:8] = 8'b11111111;     totalchardata[3][15:8] = 8'b11010011;     totalchardata[2][15:8] = 8'b11000011;     totalchardata[1][15:8] = 8'b11000011;     totalchardata[0][15:8] = 8'b11000011;      // character ‘e'     totalchardata[7][23:16] = 8'b11111111;     totalchardata[6][23:16] = 8'b11111111;     totalchardata[5][23:16] = 8'b11100000;     totalchardata[4][23:16] = 8'b11111111;     totalchardata[3][23:16] = 8'b11111111;     totalchardata[2][23:16] = 8'b11100000;     totalchardata[1][23:16] = 8'b11111111;     totalchardata[0][23:16] = 8’b11111111;   // x counter @ (posedge clock or posedge resetapp) begin     if (resetapp) begin         xaddr <= 8'b0;     end else if (pixelready) begin         if (xaddr < (width-1)) begin             xaddr <= xaddr + 8'd1;         end else begin             xaddr <= 8'b0;         end     end end  // y counter @ (posedge clock or posedge resetapp) begin     if (resetapp) begin         yaddr <= 9'b0;     end else if (pixelready && (xaddr == (width-1))) begin         if (yaddr < (height-1)) begin             yaddr <= yaddr + 9'd1;         end else begin             yaddr <= 9'b0;         end     end end   // draw characters lcd @ (posedge clock or posedge resetapp) begin     if (resetapp) begin         pixeldata[15:0] <=  16'h0000; ;     // wipe full screen background    end else begin       // whilst bitton held, make blue       if ((xaddr>=0) && (xaddr<24) && (yaddr>=0) && (yaddr<8))begin // draw complete row of pixels characters in line         if ((totalchardata[yaddr][xaddr] == 1'b1))begin  // test current bit using counters                 pixeldata[15:0] <=  16'hffe0; // yellow - draw pixel if current bit 1 defined         end         else begin             pixeldata[15:0] <=  16'h0000;          end // else       end else begin         pixeldata[15:0] <=  16'h0000;   // black screen      end     end   end 

i @ how define registers. based on how accessing them in rtl, expected them defined

reg [23:0] total_char_data [0:7] 

this in 1 line trying in 8, notice [23:0] on left side (packed array) , [0:7] on right (unpacked array) in definition. when done this, think existing assignments work.

based on though, don't know how getting 2 characters show up. have imagined looking @ it, 1 character appear, within 8x8 window. don't suppose have interesting warnings in compile things like, "outside of bit range"?