Compare two lists in my python -

i have python function has input 2 variables so-called current_level , current_affect. function calculates rules using training data , rules can calculating decisions using 2 variables current_level , current_affect. code contained 2 lists list_a , list_b. lists contained following:

list_a = [["'easy'", "'c'", "'4'", '0.714', '\n'],            ["'easy'", "'d'", "'5'", '0.778', '\n'],            ["'easy'", "'e'", "'5'", '0.500', '\n'],            ["'easy'", "'f'", "'6'", '0.750', '\n']] list_b =  [["'easy'", "'b'", "'2'", '1.000', '\n'],             ["'easy'", "'c'", "'3'", '1.000', '\n'],             ["'easy'", "'d'", "'4'", '1.000', '\n'],             ["'easy'", "'e'", "'5'", '0.875', '\n'],             ["'easy'", "'f'", "'6'", '1.000', '\n']] 

the first element of lists correspond current_level, second current_affect , third variable score. therefore want knowing input of method current_affect find of 2 lists specific case has greater score , return correspondant value 1 in case of list_a , -1 case of list_b or 0 in equality case. variable current_affect takes values between a-f. firstly, how can add non-existent current_affect values in lists. example list_a missing levels , b while list_b missing level (i want add sublists zeros) , finally, how can calculate return value?

my function following:

def association_rules_adaptation(level, current_affect): 

then in code have zipped 2 lists:

res = zip(list_a,list_b) 

withe zip want link 2 lists regarding current_affect in order able compare list has greater score specific current_affect. problem when lists doesn not contained same values of current_affect link non-similar things:

(["'easy'", "'c'", "'3'", '0.714', '\n'], ["'easy'", "'b'", "'2'", '1.000', '\n']) (["'easy'", "'d'", "'4'", '0.778', '\n'], ["'easy'", "'c'", "'3'", '1.000', '\n']) (["'easy'", "'e'", "'5'", '0.500', '\n'], ["'easy'", "'d'", "'4'", '1.000', '\n']) (["'easy'", "'f'", "'6'", '0.750', '\n'], ["'easy'", "'e'", "'5'", '0.875', '\n']) 

so want add possible values in lists in order able link them correctly , perform comparisons.

    row in res:     print (row)     print ("level", level, ": ", row[0][1])     if (row[0][2] > row[1][2]) or (row[0][2] == row[1][2]):         print ("1")     else:         print ("-1") 

edit: want check lists missing , add them lists list_a , list_b, this:

list_a = [["'easy'", "'a'", "'0'", '0', '\n'], //added sublist           ["'easy'", "'b'", "'0'", '0', '\n'], //added sublist           ["'easy'", "'c'", "'4'", '0.714', '\n'],            ["'easy'", "'d'", "'5'", '0.778', '\n'],            ["'easy'", "'e'", "'5'", '0.500', '\n'],            ["'easy'", "'f'", "'6'", '0.750', '\n']] list_b =  [["'easy'", "'a'", "'0'", '0', '\n'], //added subilst            ["'easy'", "'b'", "'2'", '1.000', '\n'],             ["'easy'", "'c'", "'3'", '1.000', '\n'],             ["'easy'", "'d'", "'4'", '1.000', '\n'],             ["'easy'", "'e'", "'5'", '0.875', '\n'],             ["'easy'", "'f'", "'6'", '1.000', '\n']] 

then zip lists , perform comparisons.

list_a = [["'easy'", "'c'", "'4'", '0.714', '\n'],            ["'easy'", "'d'", "'5'", '0.778', '\n'],            ["'easy'", "'e'", "'5'", '0.500', '\n'],            ["'easy'", "'f'", "'6'", '0.750', '\n']] list_b =  [["'easy'", "'b'", "'2'", '1.000', '\n'],             ["'easy'", "'c'", "'3'", '1.000', '\n'],             ["'easy'", "'d'", "'4'", '1.000', '\n'],             ["'easy'", "'e'", "'5'", '0.875', '\n'],             ["'easy'", "'f'", "'6'", '1.000', '\n']]  = zip(*list_a) = a[1]  b = zip(*list_b) b = b[1]  def char_range(c1, c2):     //from http://stackoverflow.com/questions/7001144/range-over-character-in-python     """generates characters `c1` `c2`, inclusive."""     c in xrange(ord(c1), ord(c2)+1):         yield chr(c)  i=0 c in char_range('a','f'):     ch = "'{}'".format(c)     if ch not in a:         list_a.insert(i, ["'easy'",ch,"'0'",'0','\n'])     if ch not in b:         list_b.insert(i, ["'easy'",ch,"'0'",'0','\n'])     i+=1  res = zip(list_a,list_b)  r in res:     if r[0][2] > r[1][2]:         print 1     elif r[0][2] < r[1][2]:         print -1     else:         print 0 

result :

0 -1 1 1 0 0